MATHEMATICS FOR IIT-JEE
10. Equation of normal in different forms
Parabola equation y² = 4ax; at point (x1,y1)
(y-y1) = (-y1/2a)* (x-x1)
In parametric form Points is (at²,2at)
y+tx = 2at + at³
Slope form, slope of the normal = m
y = mx-2am-am³
Newer Post
Older Post
Home